rossmassey.fetch-leetcode-problem

diagram of modules

This package will fetch problem info and synced code for a leetcode problem

To install:

pip install rossmassey.fetch-leetcode-problem

To use (note: output won’t be formatted):

>>> import fetch_leetcode_problem as lc

>>> lc.load_cookie()
>>> lc.update_problem_listing()
>>> info = lc.get_problem(1)
>>> print(info)
{'num': '1',
 'title': 'Two Sum',
 'slug': 'two-sum',
 'difficulty': 'Easy',
 'description': 'Given an array of integers ``nums``\xa0and an integer ``target``, return *indices of the two numbers such that they add up to ``target``*.\n\nYou may assume that each input would have ***exactly* one solution**, and you may not use the *same* element twice.\n\nYou can return the answer in any order.\n\n',
 'examples': [{'input': 'nums = [2,7,11,15], target = 9',
  'output': '[0,1]',
  'img': None,
  'explanation': ' Because nums[0] + nums[1] == 9, we return [0, 1].\n'},
 {'input': 'nums = [3,2,4], target = 6',
  'output': '[1,2]',
  'img': None,
  'explanation': None},
 {'input': 'nums = [3,3], target = 6',
  'output': '[0,1]',
  'img': None,
  'explanation': None}],
 'constraints': ['``2 <= nums.length <= 10^4``',
 '``-10^9 <= nums[i] <= 10^9``',
 '``-10^9 <= target <= 10^9``',
 '**Only one valid answer exists.**'],
 'code_snippet': 'class Solution:\n    def twoSum(self, nums: List[int], target: int) -> List[int]:\n        ',
 'code': 'class Solution:\n    def twoSum(self, nums: List[int], target: int) -> List[int]:\n        \n        complements = {}\n        \n        for i, num in enumerate(nums):\n            complements[num] = i\n            \n        for i, num in enumerate(nums):\n            if (target - num) in complements and complements[target-num] != i:\n                return [i, complements[target-num]]',
 'func': {'name': 'twoSum',
 'params': ['self', 'nums', 'target'],
 'param_types': [None, 'List[int]', 'int'],
 'rtype': 'List[int]'}}

Alternatively:

python -m fetch_leetcode_problem.main 1

  • u: update the problem index

  • c: count number of problems

  • <num>: get problem info for <num>

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